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5x-x^2=7x-63
We move all terms to the left:
5x-x^2-(7x-63)=0
We add all the numbers together, and all the variables
-1x^2+5x-(7x-63)=0
We get rid of parentheses
-1x^2+5x-7x+63=0
We add all the numbers together, and all the variables
-1x^2-2x+63=0
a = -1; b = -2; c = +63;
Δ = b2-4ac
Δ = -22-4·(-1)·63
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{256}=16$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-16}{2*-1}=\frac{-14}{-2} =+7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+16}{2*-1}=\frac{18}{-2} =-9 $
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